Problem 11
Easy First-Order PDEs

Find the general integral of the equation (∂^2 z)/(∂ x ∂ y)…

Find the general integral of the equation \[ \frac{\partial^2 z}{\partial x\,\partial y} = 0. \]

Explanation of Method

Integrate successively, once with respect to each variable; each integration introduces one arbitrary function of the variable that was held fixed.

Step 1 · Integrate once with respect to $y$

Treating $x$ as a parameter: \[ \frac{\partial z}{\partial x} = \int 0\,dy = f(x), \] where $f(x)$ is an arbitrary differentiable function of $x$ alone.

Step 2 · Integrate once more with respect to $x$

\[ z = \int f(x)\,dx + \varphi(y) = F(x) + \varphi(y), \] where $F(x) = \int f(x)\,dx$ is again an arbitrary differentiable function of $x$, and $\varphi(y)$ is an arbitrary differentiable function of $y$.


Verification

\[ \frac{\partial z}{\partial y} = \varphi'(y), \qquad \frac{\partial^2 z}{\partial x\,\partial y} = 0. \checkmark \]

Result

The general integral is:

\[ \boxed{z = F(x) + \varphi(y)} \] where $F$ and $\varphi$ are arbitrary differentiable functions of their respective arguments.