Problem 27
Easy Elimination Methods

Solve by finding first integrals the symmetric system…

Solve by finding first integrals the symmetric system: $$ \frac{dx}{x(y^2-z^2)} = \frac{dy}{-y(z^2+x^2)} = \frac{dz}{z(x^2+y^2)} $$

Explanation of Method

Adding the logarithmic rates $\dot y/y+\dot z/z$ reproduces exactly $\dot x/x$, giving a multiplicative first integral; multiplying each equation by its own variable and adding shows the nonlinear terms cancel completely, giving a conserved Euclidean norm.

  1. Add the logarithmic rates of $y$ and $z$ and compare with that of $x$.
  2. Integrate the resulting relation to get the first integral.
  3. Multiply each equation by its variable and add to eliminate the cubic terms.
  4. Integrate to get the spherical second integral.

Step 1 · First integral

With common ratio $d\tau$, $\dfrac{dy}{y}+\dfrac{dz}{z}=\bigl[-(z^2+x^2)+(x^2+y^2)\bigr]d\tau=(y^2-z^2)\,d\tau=\dfrac{dx}{x}$, so

$$ \frac{dx}{x}-\frac{dy}{y}-\frac{dz}{z}=0 \implies \frac{x}{yz}=C_1. $$

Step 2 · Spherical integral

Multiplying each equation by its own variable and adding,

$$ x\dot x+y\dot y+z\dot z=x^2(y^2-z^2)-y^2(z^2+x^2)+z^2(x^2+y^2)=0, $$

so

$$ x^2+y^2+z^2=C_2. $$

Step 3 · Verification

Differentiating $x/(yz)$ and $x^2+y^2+z^2$ along the flow shows both quantities are exactly conserved, with all cubic cross-terms cancelling. ✓


Summary Table

Quantity Value
First integral$x/(yz)=C_1$
Second integral$x^2+y^2+z^2=C_2$
Geometric picturetrajectory = sphere ∩ cubic surface

Additional Notes

Result

The first integrals of the system are:

$$ \frac{x}{yz} = C_1,\qquad x^2+y^2+z^2 = C_2 $$