Examine the stability of the rest point (0,0) of the system…
Examine the stability of the rest point $(0,0)$ of the system $$\dot{x}=10\sin x-29y+3y^3,\qquad\dot{y}=5x-14\sin y+y^2,$$ by the method of first approximation (linearisation).
Explanation of Method
The rest point's stability is determined by Lyapunov's First Method (the linearisation / first-approximation theorem). The nonlinear system is split into its linear part — the Jacobian matrix at the rest point — plus a remainder that is verified to be o(r) as the distance r to the equilibrium tends to zero. Provided no eigenvalue of the Jacobian has zero real part, those eigenvalues alone determine the stability of the full nonlinear system, and by the Hartman–Grobman theorem they also determine its qualitative type (node, saddle, or focus).
Step 1 · Verification that $(0,0)$ is a rest point
At $(0,0)$ both right-hand sides vanish.
Step 2 · Taylor expansions near $(0,0)$
Using $\sin x=x-\tfrac{x^3}{6}+\cdots$ and $\sin y=y-\tfrac{y^3}{6}+\cdots$: $$\dot x=10x-29y+\underbrace{\left(-\tfrac{5x^3}{3}+3y^3+O(r^5)\right)}_{=:f_2}=O(r^3),$$ $$\dot y=5x-14y+\underbrace{\left(y^2+\tfrac{7y^3}{3}+O(r^5)\right)}_{=:g_2}=O(r^2).$$
Step 3 · Jacobian matrix at $(0,0)$
$$A=\begin{pmatrix}10&-29\\5&-14\end{pmatrix}.$$
Step 4 · Characteristic equation
$$\det(A-\lambda I)=0\implies\lambda^2+4\lambda+5=0\implies\lambda=-2\pm i.$$
Step 5 · Classification of eigenvalues
Complex, negative real part: $\operatorname{Re}(\lambda_{1,2})=-2<0$. Stable focus of the linearisation.
Step 6 · Verification that nonlinear terms are $o(r)$
$|f_2|=O(r^3)$, $|g_2|=O(r^2)$; both are $o(r)$.
Step 7 · Application of Lyapunov's First Method
Since $\operatorname{Re}(\lambda_{1,2})<0$ and the remainders are $o(r)$, the nonlinear rest point is asymptotically stable.
Step 8 · Routh--Hurwitz verification
For $\lambda^2+4\lambda+5$: $a_1=4>0$, $a_2=5>0$.
Step 9 · Direction of rotation
At $(\varepsilon,0)$: $\dot y=5\varepsilon>0$, so the spiral is counter-clockwise.
Step 10 · Behaviour of trajectories
$r(t)\propto e^{-2t}\to0$, spiralling counter-clockwise with angular frequency $\omega=1$ and period $T=2\pi$.
Step 11 · Stability analysis
The rest point is Lyapunov stable and asymptotically stable.
Step 12 · Conclusion
$$\boxed{ (0,0)\text{ is an \textbf{asymptotically stable focus} of the nonlinear system.} }$$ The eigenvalues are $\lambda_{1,2}=-2\pm i$, with $\operatorname{Re}(\lambda_{1,2})=-2<0$. By Lyapunov's First Method, $f_2=O(r^3)$ and $g_2=O(r^2)$ are $o(r)$ and do not affect the conclusion; the rest point is an asymptotically stable focus with counter-clockwise spiralling trajectories, angular frequency $\omega=1$, period $T=2\pi$, and exponential decay rate $\alpha=2$.
Summary Table
| Quantity | Value |
|---|---|
| Eigenvalues | — |
| Classification | asymptotically stable focus |
Additional Notes
- The Hartman–Grobman theorem guarantees that, because no eigenvalue of the Jacobian is purely imaginary, the nonlinear phase portrait near the rest point is topologically equivalent to that of its linearisation — so the type found for the linear system (node, saddle, or focus) carries over unchanged to the full nonlinear system.
Result
The final classification is: