Problem 192
Medium Numerical and Functional Series

Using the Weierstrass test, show that the series sum

Using the Weierstrass test, show that the series $\displaystyle\sum_{n=1}^{\infty}\frac{\cos nx}{n^a}$ and $\displaystyle\sum_{n=1}^{\infty}\frac{\sin nx}{n^a}$ converge uniformly on $(-\infty,\infty)$ for $a>1$.

Explanation of Method

Both $|\cos nx|$ and $|\sin nx|$ are bounded by $1$ for every $x$ and $n$, so each series is dominated termwise by the convergent $p$-series $\sum1/n^a$ ($a>1$) — the textbook setup for the Weierstrass M-test, with a bound that requires no dependence on $x$ whatsoever.

  1. Bound each term by $1/n^a$, uniformly in $x$.
  2. Confirm $\sum1/n^a$ converges for $a>1$.
  3. Apply the Weierstrass M-test to conclude uniform (and absolute) convergence.

Step 1 · Uniform bound

For every $x\in\mathbb R$ and $n\ge1$: $|\cos nx|\le1$ and $|\sin nx|\le1$, so $\left|\dfrac{\cos nx}{n^a}\right|\le\dfrac1{n^a}$ and $\left|\dfrac{\sin nx}{n^a}\right|\le\dfrac1{n^a}$.

Step 2 · Majorant series

$\sum_{n=1}^{\infty}M_n=\sum_{n=1}^{\infty}1/n^a$ converges, being a $p$-series with $p=a>1$.

Step 3 · Weierstrass M-test

Both conditions of the M-test are satisfied with $M_n=1/n^a$, so both series converge uniformly and absolutely on all of $\mathbb R$.


Summary Table

SeriesMajorant $M_n$
$\sum\cos(nx)/n^a$$1/n^a$
$\sum\sin(nx)/n^a$$1/n^a$

Additional Notes

Result

Both series converge uniformly and absolutely on $\mathbb R$ for $a>1$:

$$ \sum_{n=1}^{\infty}\frac{\cos nx}{n^a}, \quad \sum_{n=1}^{\infty}\frac{\sin nx}{n^a} \text{ converge uniformly on } \mathbb R \text{ for } a>1. $$