For an airplane to be destroyed by a shell exploding at some…
For an airplane to be destroyed by a shell exploding at some distance from it, it is necessary that both engines are destroyed by shell fragments or that the pilot is killed. If a shell explodes at distance $r$ from the airplane, the probability that both engines are destroyed is $0.2$, and the probability that the pilot is killed is $0.3$. Find the probability that the airplane is knocked out by the explosion.
Explanation of Method
The airplane is knocked out if at least one of the two events occurs: $E$ = "both engines destroyed", $F$ = "pilot killed". These events can happen together, so we use the addition rule for compatible events, assuming the fragments affect the engines and the pilot independently: $P(E+F)=P(E)+P(F)-P(E)P(F)$.
Step 1: Events
$E$ = "both engines destroyed", $P(E)=0.2$; $F$ = "the pilot is killed", $P(F)=0.3$; assumed independent.
Step 2: Addition rule
\[ \boxed{P(E+F)=0.2+0.3-0.2\cdot0.3=0.44.} \]
Step 3: Check with the opposite event
The airplane survives only if the engines are not both destroyed and the pilot survives: $0.8\cdot0.7=0.56$. So $P=1-0.56=0.44$ ✓.
Step 4: Remark
Simply adding $0.2+0.3=0.5$ would count twice the case in which both happen. The answer relies on independence; if, say, the two events were mutually exclusive, the answer would be $0.5$.
Result
| Answer | |
|---|---|
| Probability | $0.2+0.3-0.06=0.44=1-0.8\cdot0.7$ |