What is the mutual gravitational potential energy of two…
What is the mutual gravitational potential energy of two point masses $m_1$ and $m_2$ a distance $r_0$ apart?
Explanation of Method
Mutual energy of two point masses.
Step 1: Idea
Potential energy is defined only up to a constant, so we must first choose where it is zero. For gravity the natural choice is when the masses are infinitely far apart, since then they no longer interact. The energy at separation $r_0$ is then minus the work we would have to do to pull the masses apart from $r_0$ to infinity.
Step 2: Work to separate them
At separation $r$ the attractive force is $\gamma m_1m_2/r^2$; we must pull with an equal force outward. Since the force changes with $r$, we integrate: \[A = \int_{r_0}^{\infty}\gamma\frac{m_1m_2}{r^2}\,dr = \gamma m_1m_2\left[-\frac1r\right]_{r_0}^{\infty},\]
\[ A = \gamma\frac{m_1m_2}{r_0}. \]
This work raises the energy from $E_p(r_0)$ to $E_p(\infty) = 0$, so $E_p(r_0) = -A$: $E_p = -\gamma\frac{m_1m_2}{r_0}$.
The energy is negative for every finite separation and becomes more negative as the masses approach. This is the mathematical expression of attraction: the system \"falls\" toward lower energy by bringing the masses together.
Check
$ -dE_p/dr = -\gamma m_1m_2/r^2 $: an attractive force of the correct size $\checkmark$
Result
\[\boxed{\,E_p = -\gamma\frac{m_1m_2}{r_0}\,}\]