Problem 23
Hard Algebraic Integrands

Evaluate the integral: integral (5 - 2x)^9 dx

Evaluate the integral: $$ \int (5 - 2x)^9 \, dx. $$

Explanation of Method

When the integrand is a power of a linear expression in $x$, the substitution $u = (\text{linear expression})$ turns it into a simple power of $u$. Because the derivative of a linear expression is constant, $dx$ converts to $du$ times a constant factor, making the substitution especially clean.

  1. Substitute $u$ for the linear expression inside the power.
  2. Convert $dx$ into $du$ using the constant derivative.
  3. Integrate the resulting power of $u$.
  4. Substitute back and add the constant of integration.

Step 1 · Use substitution

To simplify the integral, we will use the substitution method. Let:

$$ u = 5 - 2x. $$

Then, the derivative of $u$ with respect to $x$ is:

$$ \frac{du}{dx} = -2 \quad \Rightarrow \quad dx = -\frac{du}{2}. $$

Substituting into the integral, we get:

$$ \int (5-2x)^9\,dx = \int u^9 \left(-\frac{du}{2}\right) = -\frac{1}{2}\int u^9\,du. $$

Step 2 · Integrate

Now, we integrate $u^9$:

$$ \int u^9\,du = \frac{u^{10}}{10}. $$

Thus, the integral becomes:

$$ -\frac{1}{2}\int u^9\,du = -\frac{1}{2}\cdot \frac{u^{10}}{10} = -\frac{1}{20}u^{10}. $$

Step 3 · Substitute back $u = 5 - 2x$

Now, we substitute back $u = 5-2x$ into the result:

$$ -\frac{1}{20}u^{10} = -\frac{1}{20}(5-2x)^{10}. $$

Step 4 · Add the constant of integration

Finally, we add the constant of integration $C$ to the result:

$$ \int (5-2x)^9\,dx = -\frac{1}{20}(5-2x)^{10} + C. $$


Summary Table

Quantity Value
Substitution$u = 5-2x$
$dx$ in terms of $du$$-\tfrac{1}{2}du$
Antiderivative in $u$$-\tfrac{1}{20}u^{10}$

Additional Notes

Result

The solution to the integral is:

$$ \int (5-2x)^9\,dx = -\frac{1}{20}(5-2x)^{10} + C. $$