Problem 233
Do the lines tfrac x1=tfrac y2=(z-1)/(1) and tfrac…
Do the lines $\tfrac x1=\tfrac y2=\tfrac{z-1}{1}$ and $\tfrac x2=\tfrac{y-1}1=\tfrac z2$ intersect?
Explanation of Method
Deciding whether two lines intersect: here they are skew.
Step 1: Coplanarity test
Here $M_1(0,0,1)$, $\vec d_1=\{1,2,1\}$, $M_2(0,1,0)$, $\vec d_2=\{2,1,2\}$: \[\begin{vmatrix}0&-1&1\\1&2&1\\2&1&2\end{vmatrix}=0+0-3=-3\ne0 .\]
\[\text{no intersection: the lines are skew}\]
Parametric check: $s=2t$ and $1+s=2t$ would give $1=0$.
Step 2: Distance (addition)
\[ d=\frac{|[\overrightarrow{M_1M_2},\vec d_1,\vec d_2]|}{|\vec d_1\times\vec d_2|}=\frac{3}{|\{3,0,-3\}|}=\frac{3}{3\sqrt2}=\frac{\sqrt2}{2} . \]
$d=\tfrac1{\sqrt2}$
$\ell_1$
$\ell_2$
Result
\[\boxed{\,\text{no intersection: the lines are skew}\,}\]