Find all fourth roots of -4 , and identify the one with…
Find all fourth roots of $-4$, and identify the one with smallest positive argument.
Explanation of Method
Write $-4$ in polar form, apply the standard formula for $n$-th roots (equally spaced arguments), then convert the smallest-argument root back to rectangular form.
Step 1 · Polar form of $-4$
$$ -4=4\left(\cos\pi+i\sin\pi\right)=4e^{i\pi} $$
Step 2 · Apply the $n$-th root formula
The fourth roots of $4e^{i\pi}$ are:
$$ z_k=4^{1/4}\exp\left(i\,\frac{\pi+2k\pi}4\right)=\sqrt2\,\exp\left(i\,\frac{(2k+1)\pi}4\right), \qquad k=0,1,2,3 $$
giving arguments $\dfrac\pi4,\ \dfrac{3\pi}4,\ \dfrac{5\pi}4,\ \dfrac{7\pi}4$, all with modulus $\sqrt2$.
Step 3 · The root with smallest positive argument
The smallest positive argument is $\dfrac\pi4$ ($k=0$):
$$ z_0=\sqrt2\left(\cos\frac\pi4+i\sin\frac\pi4\right)=\sqrt2\left(\frac{\sqrt2}2+i\frac{\sqrt2}2\right)=1+i $$
Step 4 · Verify by direct computation
$$ (1+i)^2=1+2i-1=2i, \qquad (1+i)^4=(2i)^2=-4 \quad\checkmark $$
Step 5 · The full set of roots
$$ \boxed{z_0=1+i,\quad z_1=-1+i,\quad z_2=-1-i,\quad z_3=1-i} $$
(the four vertices of a square of side $2$ centered at the origin) — and the root with smallest positive argument is $z_0=1+i$.
Result
The four roots form a square inscribed in the circle $|z|=\sqrt2$, and $1+i$ is the one lying in the first quadrant.