Find the length of the polar subtangent and the polar
Find the length of the polar subtangent and the polar subnormal of the logarithmic spiral $\rho=a^{\varphi}$, $a>0,\ a\neq1$.
Explanation of Method
The logarithmic spiral's derivative reproduces itself, and the radius vector becomes a geometric mean.
Step 1: The two formulas
\[ S_T = \left|\frac{\rho^2}{\rho'(\varphi)}\right|, \qquad S_N = \left|\rho'(\varphi)\right|. \tag{1} \]
Step 2: Differentiate
\[ \rho' = a^{\varphi}\ln a = \rho\ln a. \tag{2} \]
Step 3: Subtangent
\[ S_T = \left|\frac{\rho^2}{\rho\ln a}\right| = \frac{\rho}{|\ln a|} = \frac{a^{\varphi}}{|\ln a|}. \tag{3} \]
Step 4: Subnormal
\[ S_N = |\rho\ln a| = \rho\,|\ln a| = a^{\varphi}\,|\ln a|. \tag{4} \]
Step 5: A companion identity
Multiplying (3) and (4): \[S_T\cdot S_N = \frac{\rho}{|\ln a|}\cdot\rho|\ln a| = \rho^2, \tag{5}\] so the radius vector is the geometric mean of the polar subtangent and the polar subnormal, at every point of the spiral.
Step 6: Verification
\[a=1.5,\ \varphi=2.0\text{: } \rho\approx2.25000,\ S_T\approx5.54898,\ S_N\approx0.91259,\ S_T S_N\approx5.06250=\rho^2\ \checkmark\]
Result
Final answer:
\[\boxed{\,S_T = \frac{\rho}{|\ln a|}, \qquad S_N = \rho\,|\ln a|, \qquad S_T\cdot S_N = \rho^2\,}\]